Home
Class 12
MATHS
Find number of four-digit numbers in whi...

Find number of four-digit numbers in which repetition is not allowed.

Text Solution

Verified by Experts


Since number is even, unit place can be filled with 0, 2, 4, 6 or 8. Also thousand's place cannot be filled with '0'.
Now number of digits available for thousand's place depend upon whether '0' is used or not at unit place.
So, here we will be having two cases.
Case I : Zero at unit place
In this case for thousand's place all nine non-zero digits are available.
The options for different places are as shown in the following figure.

So, number of numbers `=9xx8xx7=504`
Case II : Zero is not at unit place.

In this case for unit place we have four options (2,4,6 or 8)
For thousand's place, we have 8 non-zero digits available.
For hundred's place, we have again 8 digits available as digits used in thousand's place and unit place cannot be used, but digit '0' can be used.
Subsequently for ten's place we have 7 options.
So, number of numbers `=8xx8xx7xx4=1792`
Therefore, total number of numbers `=504+1792=2296`
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the number of three-digit number in which repetition is allowed and sum of digits is even.

Find the number of three-digit numbers (repetitions allowed) such that at least one of the digitsis 9

X is the number of two-digit numbers formed by 3, 5, or 7, when the repetition is allowed. Y is the number of two-digit numbers formed by 3, 5, or7, when the repetition is not allowed. Find by how much X exceeds Y.

The number of four-digit numbers strictly greater than 4321 that can be formed using the digits 0, 1, 2, 3, 4, 5 (repetition of digits is allowed) is

Write all the possible 4-digit even numbers using the digits 5, 8, 9 and 4 when the repetition is not allowed.