Ten years ago a father was six times as old as his daughter. After 10 years he will be twice as old as his daughter. Find their present age.

Ten years ago a father was six xx as old as his daughter.After 10 years he will be twice as old as his daughter.Find their present age.

A man is 4 times as old as his son. After 16 years he will be only twice as old as his son. Find their present ages.

A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.

A man is 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.

Mona's father is thrice as old as Mona. After 12 years, his age will be twice that of his daughter. Find their present ages.

5 years ago a man was 7 times as old as his son. After 5 years he will be thrice as old as his son. Find their present ages.

Form the pair of linear equations in the following problems and find their solution by substitution method : Ten years ago, father was twelve times as old as his son and ten years hence he will be twice as old as his son will be. Find their present ages.

After 25 years, Rama will be 5 times as old as he is now. Find his present age .

After 20 years, Manoj will be 5 times as old as he is now. Find his present age

Mona’s father is thrice as old as Mona. After 12 years he will be just twice his daughter. Find their present ages.