How many words can be formed using all the letters of the folloiwng words ?
(i) BANANA (ii) ALLAHABAD
INDEPENDENCE (iv) ASSASSINATION

Explanation

(i) We have word BANANA
Letters are B, (N N), (A A A).
`therefore` Number of words `=(6!)/(2!xx3!)=(6xx5xx4)/(2!)=60`
(ii) We have word ALLAHABAD
Letters are (A A A A), (L L), H,B,D
`therefore` Number of words `=(9!)/(4!xx2!)=(9xx8xx7xx6)/(2!)=1512`
(iii) We have word INDEPENDENCE
Letters are I, (N N N), (D D), (E E E E),P,C.
`therefore` Number of words `=(12!)/(3!xx2!xx4!)`
(iv) We have word ASSANSSINATION
Letters are (A A A), (S S S), (II), (N N), T, O.
`therefore` Number of words `=(13!)/(3!xx4!xx2!xx2!)`