If a+b+c=0, one root of |a-x c b c b-x a...

If `a+b+c=0,` one root of `|a-x c b c b-x a b a c-x|=0` is `x=1` b. `x=2` c. `x=a^2+b^2+c^2` d. `x=0`

A

`x=1`

B

`x=2`

C

`x=a^(2)+b^(2)+c^(2)`

D

`x=0`

Verified by Experts

The correct Answer is:

D

Operating `C_(1) to C_(1) +C_(2) +C_(3) `we get
`(a+b+c-x) |{:(1,,c,,b),(1,,b-x,,a),(1,,a,,c-x):}|=0`
`:. x=a+ b+c=0`

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