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Find the order and degree (if defined) of the equation: `((d^3y)/(dx^3))^(2/3)+4-3(d^2)/(dx^2)+5(dy)/(dx)=0`

Text Solution

Verified by Experts

The correct Answer is:
Order-3, degree-2
We have `(d^(3)y)/(dx^(3))^(2//3)+4-3(d^(2)y)/(dx^(2))+5(dy)/(dx)=0`
or `(d^(3)y)/(dx^(3))^(2)=(3(d^(2)y)/(dx^(2))-5(dy)/(dx)-4)^(3)`
Clearly, it is differential equation of degree 2 and order 3.
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