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(dy)/(dx) = (2xy)/(x^(2)-1-2y)...

`(dy)/(dx) = (2xy)/(x^(2)-1-2y)`

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Verified by Experts

The correct Answer is:
`x^(2)/2=1/y-2log_(e)y+c`
`(dy)/(dx) = (2xy)/(x^(2)-1-2y)`
or `x^(2)dy-(1-2y)dy=2xydx`
or `2xydx-x^(2)dy=-(1+2y)dy`
or `(yd(x^(2))-x^(2)dy)/(y^(2))-(1/y^(2)+2/y)dy`
or `d(x^(2)/y)=-(1/y^(2)+2/y)dy`
Integrating, we get `x^(2)/y=1/y-2logy=c`
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