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The differential equation y=px+f(p), ………...

The differential equation `y=px+f(p)`, …………..(i)
where `p=(dy)/(dx)`,is known as Clairout's equation. To solve equation i) differentiate it with respect to x, which gives either
`(dp)/(dx)=0 rArr p =c`………….(ii)
or `x+f^(i)(p)=0`…………(iii)
The number of solution of the equation `f(x)=-1` and the singular solution of the equation `y=x(dy)/(dx)+((dy)/(dx))^(2)` is

A

1

B

2

C

4

D

0

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The correct Answer is:
To solve the given problem, we will follow the steps outlined in the video transcript and derive the solutions systematically. ### Step 1: Understanding Clairaut's Equation The given differential equation is: \[ y = px + f(p) \] where \( p = \frac{dy}{dx} \). ### Step 2: Differentiate with respect to \( x \) Differentiating both sides with respect to \( x \): \[ \frac{dy}{dx} = p + x \frac{dp}{dx} + f'(p) \frac{dp}{dx} \] Since \( \frac{dy}{dx} = p \), we can substitute this into the equation: \[ p = p + x \frac{dp}{dx} + f'(p) \frac{dp}{dx} \] ### Step 3: Rearranging the Equation Rearranging gives: \[ 0 = x \frac{dp}{dx} + f'(p) \frac{dp}{dx} \] Factoring out \( \frac{dp}{dx} \): \[ \frac{dp}{dx} (x + f'(p)) = 0 \] ### Step 4: Finding Solutions This gives us two cases: 1. \( \frac{dp}{dx} = 0 \) which implies \( p = c \) (a constant). 2. \( x + f'(p) = 0 \). ### Step 5: Analyzing the First Case For the first case \( p = c \): Substituting \( p \) back into the original equation: \[ y = cx + f(c) \] This represents a family of straight lines. ### Step 6: Analyzing the Second Case For the second case \( x + f'(p) = 0 \): This implies: \[ f'(p) = -x \] This is a relationship between \( x \) and \( p \) that we need to analyze further. ### Step 7: Finding Singular Solutions To find singular solutions, we need to analyze the second case further. We have: \[ p = -\frac{x}{f'(p)} \] Substituting this back into the original equation will help us find the singular solution. ### Step 8: Solving the Given Equation \( f(x) = -1 \) We need to determine the number of solutions for the equation \( f(x) = -1 \). From the analysis, we can see that the solutions depend on the behavior of \( f'(p) \). ### Step 9: Finding Singular Solutions for \( y = x \frac{dy}{dx} + \left(\frac{dy}{dx}\right)^2 \) The equation can be rewritten as: \[ y = xp + p^2 \] Following similar steps as before, we differentiate and analyze the resulting equations to find singular solutions. ### Conclusion After analyzing both cases and substituting back into the original equations, we find that: - The number of solutions for \( f(x) = -1 \) is **2**. - The singular solution of the equation is derived from the conditions set by \( p \).

To solve the given problem, we will follow the steps outlined in the video transcript and derive the solutions systematically. ### Step 1: Understanding Clairaut's Equation The given differential equation is: \[ y = px + f(p) \] where \( p = \frac{dy}{dx} \). ### Step 2: Differentiate with respect to \( x \) ...
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The differential equation y=px+f(p) , …………..(i) where p=(dy)/(dx) ,is known as Clairout's equation. To solve equation i) differentiate it with respect to x, which gives either (dp)/(dx)=0 rArr p =c ………….(ii) or x+f^(i)(p)=0 …………(iii) The singular solution of the differential equation y=mx + m-m^(3) , where m=(dy)/(dx) , passes through the point.

The differential equation y=px+f(p) , …………..(i) where p=(dy)/(dx) ,is known as Clairout's equation. To solve equation i) differentiate it with respect to x, which gives either (dp)/(dx)=0 rArr p =c ………….(ii) or x+f^(i)(p)=0 …………(iii) Which of the following is true about solutions of differential equation y=xy^(')+sqrt(1+y^('2)) ?

The solution of the differential equation (dy)/(dx)+(y)/(x)=x^(2) , is

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The general solution of differential equation (dy)/(dx)=(x+y)/(x-y) is

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