If the area of bounded between the x-axis and the graph of `y=6x-3x^2`
between the ordinates `x=1a n dx=a`
is `19`
units, then `a`
can take the value
`4or-2`
two value are in (2,3) and one
in `(-1,0)`
two value are in (3,4) and one in
`(-2,-1)`
none of these
A
one value in (2, 3)
B
one value in `(-2, -1)`
C
one value in `(-1,0)`
D
one value in `(3,4)`
Text Solution
Verified by Experts
The correct Answer is:
B, D
`I=int(6x-3x^(2))dx=(6x^(2))/(2)-(3x^(3))/(3)=3x^(2)-x^(3)=x^(2)(3-x)` `A_(1)=I(2)-I(3)=4-2=2" units"` `A_(2)=I(2)-I(3)=4-0=4" units"` `A_(3)=I(3)-I(4)=0-(-16)=16" units"` `rArr" one value of a will lie in "(3, 4)`. Using symmetry, order will lie i `(-2,-1)`
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If the area of bounded between the x-axis and the graph of y=6x-3x^(2) between the ordinates x=1 and x=a is 19 units,then a can take the value (A) 4 or -2 (B) two value are in (2,3) and one in (-1,0) (C) two value are in (3,4) and one in (-2,-1)( D) none of these
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