Escape velocity on the surface of earth is 11.2 km/s . Escape velocity from a planet whose mass is the same as that of earth and radius 1/4 that of earth is

Options

A. 11.2 km/s
B. 22.4 km/s
C. 5.6 km/s
D. 44.8 km/s

Answer

B

Explanation

`V_(es)` for earth is 11.2 km/sec
`V_(es) = sqrt((2GM_(e))/(R_(e))) = 11.2` km/sec
`V_(es) = sqrt((2GM_(e) xx 4)/(R_(e ))) = .^(2)sqrt((@GM_(e))/(R_(e)))`
`= 2 xx 11.2 = 22.4` km/sec