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If |vecA+vecB|=|vecA|+|vecB|, then angle...

If `|vecA+vecB|=|vecA|+|vecB|`, then angle between `vecA` and `vecB` will be

A

`90^@`

B

`120^@`

C

`0^@`

D

`60^@`

Text Solution

Verified by Experts

The correct Answer is:
B

`|vecA+vecB|^2=A^2+B^2+2AB cos theta`
`rArr A^2=A^2+A^2+2A^2 cos theta`
`rArr cos theta =-1/2 rArr theta=120^@`
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