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In an inductor of self-inductance L=2 mH...

In an inductor of self-inductance L=2 mH, current changes with time according to relation `i=t^(2)e^(-t)`. At what time emf is zero ?

A

2s

B

1s

C

4s

D

3s

Text Solution

Verified by Experts

The correct Answer is:
A
`I=t^2e^(-t)`
`e=L"dl"/"dt"` here emf is zero when `"dl"/"dt"=0`
`"dl"/"dt"=2te^(-tau)-t^2 e^(-tau)=0`
`rArr te^(-tau) (t-2) = 0 rArr t =2` sec
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