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Consider two rods of same length and dif...

Consider two rods of same length and different specific heats (`S_1` and `S_2`), conductivities `K_1` and `K_2` and area of cross section (`A_1` and `A_2`) and both having temperature `T_1` and `T_2` at their ends. If the rate of heat loss due to conduction is equal then

A

`K_1A_1=K_2A_2`

B

`(K_1A_1)/S_1=(K_2A_2)/S_2`

C

`K_2A_1=K_1A_2`

D

`(K_2A_1)/S_2=(K_1A_2)/S_2`

Text Solution

Verified by Experts

The correct Answer is:
A
Use `"dQ"/"dt"="KA"/L(T_1-T_2)`
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