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The efficiency of carnot engine is 50% a...

The efficiency of carnot engine is 50% and temperature of sink is 500K. If temperature of source is kept constant and its efficiency raised to 60%, then the required temperature of the sink will be : -

A

100 K

B

600 K

C

400 K

D

500 K

Text Solution

Verified by Experts

The correct Answer is:
C
% n =`(1-T_2/T_1)xx100`
For 50% `50/100 =1-500/T_1 rArr T_1=1000 K`
For 60% `60/100`=1-`T_2/1000 rArr T_2`=400 K
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