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If kinetic energy of a body is increased...

If kinetic energy of a body is increased by 300%, then percentage change in momentum will be

A

`100%`

B

`150%`

C

`265%`

D

`73.2%`

Text Solution

Verified by Experts

The correct Answer is:
A
`P_1=sqrt(2mE_1) , P_2=sqrt(2mE_2)`
`=sqrt(2m(E_1+300/100E_1))=sqrt(2m(4E_1))=2P_1`
% change `=(P_2-P_1)/P_1xx100=(2P_2-P_1)/P_1xx100=100%`
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