A particle moves along a circle if radius (20 //pi) m with constant tangential acceleration. If the velocity of the particle is ` 80 m//s` at the end of the second revolution after motion has begun the tangential acceleration is .

Options

A. `"40 m/s"^(-2)`
B. `640 pi "m/s"^(-2)`
C. `160 pi"m/s"^(-2)`
D. `40 pi "m/s"^(-2)`

Answer

A

Explanation

Here `"dv"/"dt"`=constant =a (say)
use `v^2=u^2+2as` where `s=2xx2pir`=80 m, u=0 , v=80 m/s