A ball rolls without slipping. The radius of gyration of the ball about an axis passing through its centre of mass is `k`. If radius of the ball be `R`, then the fraction of total energy associated with its rotation will be.

Options

A. `(K^2+R^2)/R^2`
B. `K^2/R^2`
C. `K^2/(K^2+R^2)`
D. `R^2/(K^2+R^2)`

Answer

C

Explanation

T.K.E.=`1/2mv^2(1+K^2//R^2)`
R.K.E.=`1/2mv^2(K^2//R^2)`