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An electron is moving round the nucleus ...

An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius `r`. The coulomb force `vec(F)` between the two is (where `k=(1)/(4piepsilon_(0)))`

A

`K e^2/r^2 hatr`

B

`-K e^2/r^3 hatr`

C

`K e^2/r^3 vecr`

D

`-K e^2/r^3 vecr`

Text Solution

Verified by Experts

The correct Answer is:
D
Coulomb force =`(Ke^2)/r^2(-hatr)`
`=-(Ke^2)/r^3 vecr`
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