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The dimensions of universal gravitationa...

The dimensions of universal gravitational constant are :-

A

`ML^2 T^(-1)`

B

`M^(-2)L^3 T^(-2)`

C

`M^(-2) L^2 T^(-1)`

D

`M^(-1) L^3 T^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`because F=(Gm_1m_2)/r^2`
`therefore [G] =[(Fr^2)/m^2]=(MLT^(-2)L^2)/M^2`
`=M^(-1)L^3T^(-2)`
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