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A block of mass m is placed on a smooth...

A block of mass m is placed on a smooth wedge of inclination `theta`. The whole system is accelerated horizontally, so that the block does not slip on the wedge. The force exerted by the wedge on the block (g is acceleration due to gravity) will be

A

mg sin `theta`

B

mg

C

mg/cos `theta`

D

mg cos `theta`

Text Solution

Verified by Experts

The correct Answer is:
C

Here `N cos theta =mg rArr N = "mg"/(cos theta)`
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