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One mole of an ideal gas at an initial t...

One mole of an ideal gas at an initial temperature true of `TK` does `6R` joule of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is `5//3`, the final temperature of the gas will be

A

(T –2.4) K

B

(T + 4)K

C

(T – 4) K

D

(T + 2.4)K

Text Solution

Verified by Experts

The correct Answer is:
C

`DeltaU=muC_vDeltaT` and 0 = W + `DeltaU`
`rArr DeltaU=-6R(therefore W=6R)`
Therefore -6R = `1(R/(gamma-1))DeltaT=3/2RDeltaT`
`=DeltaT=-4 rArr T_"final"=(T-4) K`
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