A particle executing simple harmonic mot...

A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm / s . The frequency of its oscillation is

A

1 Hz

B

3 Hz

C

2 Hz

D

4 Hz

Text Solution

Verified by Experts

The correct Answer is:

A

`V_(max)= a omega implies f=(omega)/(2pi)=(V_(max))/(2pia)=(31.4)/(2pixx5)`
`=(31.4)/(10 pi)=1 Hz`

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