A particle executes simple harmonic oscillation with an amplitudes a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is

Options

A. T/2
B. T/4
C. T/8
D. T/12

Answer

D

Explanation

`:' x= a sin omega t`
` :. (a)/(2)=a sin omegatimplies omega t=(pi)/(6)`
`implies ((2pi)/(T))t=(pi)/(6)impliest=(T)/(12)`