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Three resistance P, Q, R each of 2 Omega...

Three resistance `P, Q, R` each of `2 Omega` and an unknown resistance `S` from the four amrs of a Wheatstone's bridge circuit. When a resistance of `6 Omega` is connected in parallel to `S` the bridge gets balanced. What is the value of `S` ?

A

`1 Omega `

B

`2 Omega `

C

`3 Omega `

D

`6 Omega `

Text Solution

Verified by Experts

The correct Answer is:
C

for balanced wheatstone bridge circuit
`(2)/(2)=(2)/(((6S)/(S+6)))implies S+6=3S implies S=3 Omega `
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