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A long solenoid has 500 turns. When a cu...

A long solenoid has `500` turns. When a current of `2A` is passed through it, the resulting magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb` . The self-inductance of the solenoid is

A

1.0 henry

B

4.0 henry

C

2.5 henry

D

2.0 henry

Text Solution

Verified by Experts

The correct Answer is:
A
`"Flux linkage "="Flux through each turn"xx"number of turn"`
`phi=500xx4xx10^(-3)=2Wb`
since `phi=Li`
`rArr L=(phi)/(i)=(2)/(2)=1H`
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