Two nuclei have their mass numbers in the ratio of `1:3`. The ratio of their nuclear densities would be

Options

A. `(3)^(1//3):1`
B. `1:1`
C. `1:3`
D. `3:1`

Answer

B

Explanation

`R=R_(0).A^(1//3)`
So nuclear density `=(A.m)/(v)`
m = mass of each nucleon, A = mass number
`=(3m)/(4piR_(0)^(3))=" independent of A."`