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If the error in the measurement of radiu...

If the error in the measurement of radius of a sphere in `2%` then the error in the determination of volume of the spahere will be

A

`8%`

B

`2%`

C

`4%`

D

`6%`

Text Solution

Verified by Experts

The correct Answer is:
D

`V=(4)/(3)pir^(3)`
`(DeltaV)/(V)xx100=3xx((Deltar)/(r)xx100)`
`%" error in volume "=3xx 5" error in radius"`
`=3xx2=6%`
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