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In any AC circuit the emf (e) and the cu...

In any `AC` circuit the emf `(e)` and the current `(i)` at any instant are given respectively by `e= E_(0)sin omega t`
`i=I_(0) sin (omegat-phi)`
The average power in the circuit over one cycle of `AC` is

A

`(E_(0)I_(0))/(2)cosphi`

B

`E_(0)I_(0)`

C

`(E_(0)I_(0))/(2)`

D

`(E_(0)I_(0))/(2)sin phi`

Text Solution

Verified by Experts

The correct Answer is:
A
`e=E_(0)sin omegat`
`i=I_(0) sin (omegat-phi)`
`P_(av.)=e_("rms").I_("rms").cos phi`
`(E_(0))/(sqrt2).(I_(0))/(sqrt2). cosphi = E_(0)I_(0)cosphi`
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