If the dimension of a physical quantity are given by `M^a L^b T^c,` then the physical quantity will be

Options

A. Force if a = 0, b = –1, c = –2
B. Pressure if a = 1, b = –1, c = –2
C. Velocity if a = 1, b = 0, c = –1
D. Acceleration if a = 1, b = 1, c = –2

Answer

B

Explanation

`[P]=(F)/(A)=[(MLT^(-2))/(L^(2))]=[ML^(-1)T^(-2)]`