A simple pendulum simple harmonic motion about `x = 0` with an amplitude a and time period `T` speed of the pendulum at `x = a//2` will be

Options

A. `(piasqrt(3))/(T)`
B. `(piasqrt(3))/(2T)`
C. `(pia)/(T)`
D. `(3 pi^(2)a)/(T)`

Answer

A

Explanation

`v=omega sqrt(A^(2)-x^(2))`
`=(2pi)/(T)sqrt(a^(2)-(a^(2))/(T))=(pia sqrt(3))/(T)`