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A vibration magnetometer placed in magne...

A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet will be

A

1s

B

2s

C

3s

D

4s

Text Solution

Verified by Experts

The correct Answer is:
D
`T=2pisqrt((1)/(MB_(H))),T'=2pisqrt((I)/(M(B_(H)-B)))`
`implies T'=2T=4s`
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