A particle of mass `m` is thrown upwards from the surface of the earth, with a velocity `u`. The mass and the radius of the earth are, respectively, `M` and `R`. `G` is gravitational constant `g` is acceleration due to gravity on the surface of earth. The minimum value of `u` so that the particle does not return back to earth is

Options

A. `sqrt((2GM)/(R^(2)))`
B. `sqrt((2GM)/(R))`
C. `sqrt((2gM)/(R^(2)))`
D. `sqrt(2gR^(2))`

Answer

B

Explanation

`v_("escape")=sqrt((2GM)/(R))`
Escape velocity from the earth surface.