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Two particles execute simple harmonic mo...

Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each other moving in opposite directions each time their displacement is half their amplitude. Their phase difference is

A

`pi/6`

B

0

C

`2pi/3`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
C

Time interval `=T/6+T/6=(2T)/(6)`
Phase difference `implies (2T)/(6)-=(2pi)/(3)`
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