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An electron in the hydrogen atom jumps f...

An electron in the hydrogen atom jumps from excited state `n` to the ground state. The wavelength so emitted illuminates a photo-sensitive material having work function `2.75eV`. If the stopping potential of the photoelectron is `10V`, the value of `n` is

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(ph)=K.E_max+W`
`=eV_0+W=10+2.75=12.75eV`

Differenced of 4 and 1 energy level is 12.75 eV So higher energy level is 4 to ground and Excited state is n = 3.
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