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Lights of two different frequencies whose photons have energies 1 and 2.5 eV, respectively, successively illuminate a metal whose work function is 0.5 eV. The ratio of the maximum speeds of the emitted electrons

A

`1:2`

B

`1:1`

C

`1:5`

D

`1:4`

Text Solution

Verified by Experts

The correct Answer is:
A

`v_("max")=sqrt((2)/(m)(KE_("max")))=sqrt((2)/(m)(E_(Ph)-W))`
`(v_(1))/(v_(2))=sqrt((1-0.5)/(2.5-0.5))=sqrt((0.5)/(2))=1:2`
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