A stone is dropped from a height `h` . It hits the ground with a certain momentum `P` . If the same stone is dropped from a height `100%` more thanthe preyiious height, the momentum when it hits the ground will change by

Options

A. `41%`
B. `200%`
C. `100%`
D. `68%`

Answer

A

Explanation

`v=sqrt(2gh)`
`"P = mv = m"sqrt(2gh)`
`P prop sqrth`
`(P_(2))/(P_(1))=sqrt((h_(2))/(h_(1)))=sqrt((2h)/(h))=sqrt2`
`P_(2)=1.414P_(1)`
`%" change"=(P_(2)-P_(1))/(P_(1))xx100%`
`=41.4%`