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The potential energy of a particle in a ...

The potential energy of a particle in a force field is:
`U = (A)/(r^(2)) - (B)/(r )`,. Where `A` and `B` are positive
constants and `r` is the distance of particle from the centre of the field. For stable equilibrium the distance of the particle is

A

`A//B`

B

`B//A`

C

`B//2A`

D

`2A//B`

Text Solution

Verified by Experts

The correct Answer is:
D
For Stable equilibrium, `F=(dU)/(dr)=0`
we get `r=2A//B`
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