A spherical planet far out in space has a mass `M_(0)` and diameter `D_(0)`. A particle of mass m falling freely near the surface of this planet will experience an accelertion due to gravity which is equal to

Options

A. `GM_(P)//D_(P)^(2)`
B. `4GM_(P)m//D_(P)^(2)`
C. `4GM_(P)//D_(P)^(2)`
D. `GM_(P)m//D_(P)^(2)`

Answer

C

Explanation

`g=(GM_(P))/(R_(P)^(2)) " where " R_(P)=D_(P)//2`