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The height a which the weight of a body ...

The height a which the weight of a body becomes `1//16th` its weight on the surface of earth (radius `R`) is

A

3R

B

4R

C

5R

D

15R

Text Solution

Verified by Experts

The correct Answer is:
A
`(W_(h))/(W)=(mg)/(mg)=((R )/(R+h))^(2)=(1)/(16)`
`therefore h=3 R`
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