A milli-voltmeter of 25 milli-volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be:

Options

A. 1
B. 0.05
C. 0.001
D. 0.01

Answer

C

Explanation

If the resistance of the meter is G then the full scale deflection current `i_(g)=(25 mV)/(G)` ampere
The Value of shunt required for converting it into ammeter of range 25 ampere is `S=(i_(g)G)/(i-i_(g))`
So `~~(25 mV)/(25)=0.001 Omega`