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In an experiment four quantities a,b,c a...

In an experiment four quantities a,b,c and d are measure with percentage error `1% , 2% , 3%`,and `4%` respectively quantity is P is calculate as follow
`P = (a^(3)b^(2))/(cd) %` error in `P` is

A

`14%`

B

`10%`

C

`7%`

D

`4%`

Text Solution

Verified by Experts

The correct Answer is:
A
`P=(a^(3)b^(2))/(cd)`
Error in `((DeltaP)/(P))=3((Deltaa)/(a))+2((Deltab)/(b))+((Deltac)/(c))+((Deltad)/(d))`
`=3(1%)+2(2%)+3%+4%=14%`
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