A uniform force of (3hati+hatj) N acts o...

A uniform force of `(3hati+hatj)` N acts on a particle of mass 2kg. Hence, the particle is displaced from position `(2hati+hatk)`m to position `(4hati+3hatj-hatk)`m. The work done by the force on the particle is

9 J

6 J

13 J

15 J

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The correct Answer is:

Displacement `=vecr_(2)-vecr_(1)=(4hati+3hatj-hatk)-(2hati+hatk)`
`=2hati + 3 hatj- 2 hatk `
Force `vecF=3hati+hatj`
Work `W=vecF.vecd=(3hati+hatj).(2hati+3hatj-2hatk)`
`=6+3=9J`

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