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A coil of self-inductance L is connected...

A coil of self-inductance `L` is connected in series with a bulb `B` and an `AC` source. Brightness of the bulb decreases when

A

frequency of the AC source is decreased

B

number of turns in the coil is reduced

C

a capacitance of reactance `X_(C)=X_(L)` is included in the same circuit

D

an iron rod is inserted in the coil

Text Solution

Verified by Experts

The correct Answer is:
D

`L=(mu_(0)mu_(r)N^(2)A)/(l)`

`darrI=(E)/(sqrt(omega^(2)L^(2)+R^(2)))=(E)/(sqrt(omega^(2)L^(2)uarr+R^(2)))`
`L prop mu_(r)`
L is increased when iron rod inserted
So current decreased
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