In the spectrum of hydrogen atom, the ratio of the longest wavelength in Lyman series to the longest wavelangth in the Balmer series is:

Options

A. `(5)/(27)`
B. `(3)/(23)`
C. `(7)/(29)`
D. `(9)/(31)`

Answer

A

Explanation

`(1)/(lambda_(l)) =R(1)^(2) [(1)/(1^(2))-(1)/(2^(2))]=(3R)/(4) `
`lambda_(l)=(4)/(3R) " "....(1) `
` (1)/(lambda_(b))=R(1)^(2)[ (1)/(2^(2))-(1)/(3^(2))] = (5R)/(36) `
` lambda_(b)=(36)/(5R) " "....(2) `
` (lambda_(l))/(lambda_(b))=(4)/(3R) xx (5R)/(36) = (5)/(3 xx 9) = (5)/(27) `