The cylinderical tube of a spray pump has radius R, One end of which has n fine holes, each of radius r. If the speed of the liquid in the tube is V, the speed of the ejection of the liquid through the holes is :

Options

A. `(V^(2)R)/(nr)`
B. `(VR^(2))/(n^(2)r^(2))`
C. `(VR^(2))/(nr^(2))`
D. `(VR^(2))/(n^(3)r^(2))`

Answer

C

Explanation

`A_(1)V_(1)=A_(2)V_(2)` ltBrgt `impliesV_(2)=(A_(1)V_(1))/(A_(2))=(piR^(2)xxV)/(n(pir^(2)))`
`=(R^(2))/(nr^(2))V`