A parallel plate air capacitor has capcity `C` distance of separtion between plates is `d` and potential difference `V` is applied between the plates force of attraction between the plates of the parallel plate air capacitor is

Options

A. `(C^(2)V^(2))/(2d^(2))`
B. `(C^(2)V^(2))/(2d)`
C. `(CV^(2))/(2d)`
D. `(CV^(2))/(d)`

Answer

C

Explanation

Force between plate
of capacitor
`F=qE`
`=q((q)/(2Ain_(0)))`
`F=(q^(2))/(2Ain_(0))`
`thereforeq=CV`
`F=(C^(2)V^(2))/(2Ain_(0))`
`F=(((Ain_(0))/(d))CV^(2))/(2Ain_(0))`
`F=(CV^(2))/(2d)`