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A photoelectric surface is illuminated s...

A photoelectric surface is illuminated successively by monochromatic light of wavelength `lambda` and `(lambda)/(2)`. If the maximum kinetic energy of the emitted photoelectrons in the second case is `3` times than in the first case , the work function of the surface of the material is
(`h` = Plank's constant , `c` = speed of light )

A

`(hc)/(3lamda)`

B

`(hc)/(2lamda)`

C

`(hc)/(lamda)`

D

`(2hc)/(lamda)`

Text Solution

Verified by Experts

The correct Answer is:
B

`k_(max)=E-phi`
`k=(hc)/(lamda)-phi` . . (1)
`3k=(hc)/((lamda//2))-phi` . . . (2)
On solving
`phi=(hc)/(2lamda)`
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