A satellite of mass `m` is orbiting the earth (of radius `R`) at a height `h` from its surface. The total energy of the satellite in terms of `g_(0)`, the value of acceleration due to gravity at the earth's surface,

Options

A. `(mg_(0)R^(2))/(2(R+h))`
B. `-(mg_(0)R^(2))/(2(R+h))`
C. `(2mg_(0)R^(2))/(R+h)`
D. `-(2mg_(0)R^(2))/(R+h)`

Answer

B

Explanation

`T.E=-(GMm)/(2r)`
`thereforeg_(0)=g_("surface")=(GM)/(R^(2))`
`GM=g_(0)R^(2)` ltBrgt `T.E=-(g_(0)R^(2)m)/(2(R+h))`