A `100 Omega` resistance and a capacitor of `100 Omega` reactance are connected in series across a `220` V source. When the capacitor is `50%` charged, the peak value of the displacement current is

Options

A. 2.2 A
B. `11A`
C. 4.4 A
D. 11`sqrt(2)A`

Answer

A

Explanation

`X_(C)=100`
`R=100`
`Z=sqrt((100)^(2)+(100)^(2))=100sqrt(2)`
`I=(E)/(Z)=(220)/(100sqrt(2))=(2.2)/(sqrt(2))`
`I_(0)=sqrt(2)I=(2.2)/(sqrt(2))xxsqrt(2)=2.2A`