For CE transistor amplifier, the audio signal voltage across the collector resistance of `2 kOmega` is 4V. If the current amplification factor of the transistor is 100 and the base resistance is `1kOmega`, then the input signal voltage is

Options

A. 10 mV
B. 20 mV
C. 30 mV
D. 15 mV

Answer

B

Explanation

`beta=100`
`R_(C)=2kOmega`
`V_(0)=4V`
`R_(B)=1kOmega`
`A=(V_(0))/(V_(i))=beta(R_(C))/(R_(B))`
`V_(i)=(V_(0)xxR_(B))/(betaR_(C))=(4xx10)/(100xx2xx10^(3))=20mV`