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A 250-turns recantagular coil of length...

A 250-turns recantagular coil of length 2.1 cm and width 1.25 cm carries a current of `85 muA` and subjected to magnetic field of strength `0.85 T`. Work done for rotating the coil by `180^(@)` against the torque is

A

`9.1 mu J`

B

` 4.55 mu J`

C

`2.3 muJ`

D

`1.15 muJ`

Text Solution

Verified by Experts

The correct Answer is:
A

`W=MB(cos theta_(1)- cos theta_(2))`
When it is rotated by angle `180^(@)` then
W=2MB
W =2(NIA) B
`=2xx250xx85xx10^(-6)[1.25xx2.1xx10^(-4)]xx85xx10^(-2)`
`=9.1 muJ`
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